[20191031]完善vim的bccalc插件7.txt

来源:https://www.cnblogs.com/lfree/archive/2019/10/31/11773465.html
-Advertisement-
Play Games

[20191031]完善vim的bccalc插件7.txt--//增加/ 2^16 %2^16功能,輸入\tx,例子:1398145029 = /2^16 %2^16 (type and mode) = 21334,5 = 0x535600050x53560005 = /2^16 %2^16 (ty ...


[20191031]完善vim的bccalc插件7.txt

--//增加/ 2^16 %2^16功能,輸入\tx,例子:
1398145029 = /2^16  %2^16 (type and mode) = 21334,5 = 0x53560005
0x53560005 = /2^16  %2^16 (type and mode) = 21334,5 = 1398145029
--//5356 =SV(對應asc碼SV)

--//增加處理輸入逗號過濾問題,這個有點麻煩的是有時候逗號是合法的。單獨增加快捷使用\c,
--//而\bc的功能不動。

noremap   <Leader>c, Yp!!sed "s/,//g" \|bc -lq\| tr -d '\n\\\r' \| sed -e "s/\.\([0-9]*[1-9]\)0\+$/.\1/" -e "s/\.0\+$//"<CR>kA = <ESC>J

12,345+1,000 = 13345  --//輸入\c.

--//代碼如下bccalc_win.vim:

"" calculate expression entered on command line and give answer, e.g.:
" :Calculate sin (3) + sin (4) ^ 2
command! -nargs=+ Calculate echo "<args> = " . Calculate ("<args>",0)

"" calculate expression from selection, pick a mapping, or use the Leader form
vnoremap ;bc "ey`>:call CalcLines(0)<CR>
vnoremap ;bb "ey`>:call CalcLines(0)<CR>

vnoremap ;10 "ey`>:call CalcLines(10)<CR>
vnoremap ;16 "ey`>:call CalcLines(16)<CR>

vnoremap ;tx "ey`>:call CalcLines(1616)<CR>

vnoremap ;22 "ey`>:call CalcLines(22)<CR>
vnoremap ;dba "ey`>:call CalcLines(22)<CR>

vnoremap ;32 "ey`>:call CalcLines(32)<CR>
vnoremap ;scn "ey`>:call CalcLines(32)<CR>

vnoremap ;ss "ey`>:call CalcLines(10016)<CR>
vnoremap ;rr "ey`>:call CalcLines(20016)<CR>
vnoremap ;hd "ey`>:call CalcLines(30016)<CR>
vnoremap ;hh "ey`>:call CalcLines(30016)<CR>
vnoremap ;dh "ey`>:call CalcLines(30016)<CR>

"" calculate expression on current line, pick a mapping, or use the Leader
nnoremap  <Leader>bx <Esc>A <Esc>"eyy$:call CalcLines(0)<CR>
nnoremap  <Leader>bc <Esc>A = <Esc>"eyy:call CalcLines(0)<CR>
nnoremap  <Leader>bb <Esc>A = <Esc>"eyy:call CalcLines(0)<CR>
"noremap   <Leader>cc Yp!!bc -lq<CR>kA = <ESC>J
noremap   <Leader>cc Yp!!bc -lq\| tr -d '\n\\\r' \| sed -e "s/\.\([0-9]*[1-9]\)0\+$/.\1/" -e "s/\.0\+$//"<CR>kA = <ESC>J
noremap   <Leader>c, Yp!!sed "s/,//g" \|bc -lq\| tr -d '\n\\\r' \| sed -e "s/\.\([0-9]*[1-9]\)0\+$/.\1/" -e "s/\.0\+$//"<CR>kA = <ESC>J

" convert hexdecimal to decimal
nnoremap  <Leader>10 <Esc>A = <Esc>"eyy:call CalcLines(10)<CR>

" convert decimal to hexdecimal
nnoremap  <Leader>16 <Esc>A = <Esc>"eyy:call CalcLines(16)<CR>

" split event P1 to TYPE and MODE
nnoremap  <Leader>tx  <Esc>A = <Esc>"eyy:call CalcLines(1616)<CR>

" split dba(10) or dba(16) to file# and block#
nnoremap  <Leader>22  <Esc>A = <Esc>"eyy:call CalcLines(22)<CR>
nnoremap  <Leader>dba <Esc>A = <Esc>"eyy:call CalcLines(22)<CR>

" split scn(10) or scn(16) into scn_wrap,scn_base
nnoremap  <Leader>32  <Esc>A = <Esc>"eyy:call CalcLines(32)<CR>
nnoremap  <Leader>scn <Esc>A = <Esc>"eyy:call CalcLines(32)<CR>

" convert scn_wrap,scn_base(10) or scn_wrap,scn_base(16) to 10 or 16 base
nnoremap  <Leader>ss <Esc>A = <Esc>"eyy:call CalcLines(10016)<CR>

" convert file#,block# dba(10) or file#,block# dba(16) to 10 or 16 base
nnoremap  <Leader>rr <Esc>A = <Esc>"eyy:call CalcLines(20016)<CR>

" convert hexdecimal to decimal or decimal to hexdecimal
nnoremap  <Leader>hd <Esc>A = <Esc>"eyy:call CalcLines(30016)<CR>
nnoremap  <Leader>hh <Esc>A = <Esc>"eyy:call CalcLines(30016)<CR>
nnoremap  <Leader>dh <Esc>A = <Esc>"eyy:call CalcLines(30016)<CR>

"" calculate from insertmode
inoremap =: = <Esc>"eyy:call CalcLines(0)<CR>a

" ---------------------------------------------------------------------
"  Calculate:
"    clean up an expression, pass it to bc, return answer
function! Calculate (s,flag)

    let has_hex = 0
    let str = a:s

    " remove newlines and trailing spaces
    let str = substitute (str, "\n",   "", "g")
    let str = substitute (str, '\s*$', "", "g")

    " sub common func names for bc equivalent
    let str = substitute (str, '\csin\s*(',  's (', 'g')
    let str = substitute (str, '\ccos\s*(',  'c (', 'g')
    let str = substitute (str, '\catan\s*(', 'a (', 'g')
    let str = substitute (str, "\cln\s*(",   'l (', 'g')
    let str = substitute (str, '\clog\s*(',  'l (', 'g')
    let str = substitute (str, '\cexp\s*(',  'e (', 'g')

    " alternate exponitiation symbols
    let str = substitute (str, '\*\*', '^', "g")
    let str = substitute (str, '`', '^',    "g")
    let str = substitute (str, '\^', '^^^^',    "g")

    " escape chars for shell
    if has("unix")
        let str = escape (str, '*();&><|^')
    endif

    let preload = exists ("g:bccalc_preload") ? g:bccalc_preload : ""

    " run bc
    " return str
    " let answer = system ("echo " . str . " \| bc -l " . preload)

    if a:flag == 0
         let answer = system ("echo " . str . " \| bc -l " . preload)
         " let answer = answer . " --- ". str
    endif

    if a:flag == 10
        let str = toupper (str)
        let str = substitute (str, "0x", "", "g")
        let answer = system ("echo ibase=16 ;" . str .  " \| bc -l " . preload)
    endif

    if a:flag == 16
        let answer = system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
        let answer = "0x" . tolower ( answer )
    endif

    let has_hex = Check_hex(str)

    if a:flag == 1616
        if has_hex == 1
            let str = toupper (str)
            let str = substitute (str, "0x", "", "g")
            " 0x10000 hexdecimal = 65536 (10) = 2^16(10)
            let answer  = system ("echo ibase=16 ;" . str . "/10000" . " \| bc " . preload)
            let answer1 = system ("echo ibase=16 ;" . str . "%10000" . " \| bc " . preload)
            let answer2 = system ("echo ibase=16 ;" . str .  " \| bc -l " . preload)
        else
            let answer  = system ("echo " . str . "/65536" . " \| bc " . preload)
            let answer1 = system ("echo " . str . "%65536" . " \| bc " . preload)
            let answer2 = "0x" . system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
        endif
        let answer = "/2^16  %2^16 (Type | Mode) = " . answer . "," . answer1 ." = " . tolower(answer2)
    endif

    if a:flag == 22
        if has_hex == 1
            let str = toupper (str)
            let str = substitute (str, "0x", "", "g")
            " 0x400000 hexdecimal = 4194304 (10) = 2^22(10)
            let answer  = system ("echo ibase=16 ;" . str . "/400000" . " \| bc " . preload)
            let answer1 = system ("echo ibase=16 ;" . str . "%400000" . " \| bc " . preload)
            let answer2 = system ("echo ibase=16 ;" . str .  " \| bc -l " . preload)
        else
            let answer  = system ("echo " . str . "/4194304" . " \| bc " . preload)
            let answer1 = system ("echo " . str . "%4194304" . " \| bc " . preload)
            let answer2 = "0x" . system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
        endif
        " let answer = "set dba " . answer . "," . answer1
        let answer = "set dba " . answer . "," . answer1 ." = alter system dump datefile " . answer . " block " . answer1 ." = " . tolower(answer2)
    endif

    if a:flag == 32
        if has_hex == 1
            let str = toupper (str)
            let str = substitute (str, "0x", "", "g")
            " 0x100000000 hexdecimal = 4294967296(10) = 2^32(10)
            let answer  = system ("echo ibase=16 ;" . str . "/100000000" . " \| bc " . preload)
            let answer1 = system ("echo ibase=16 ;" . str . "%100000000" . " \| bc " . preload)
            let answer2 = system ("echo obase=16 ;ibase=16 ;" . str . "/100000000" . " \| bc " . preload)
            let answer3 = system ("echo obase=16 ;ibase=16 ;" . str . "%100000000" . " \| bc " . preload)
        else
            let answer  = system ("echo " . str . "/4294967296" . " \| bc " . preload)
            let answer1 = system ("echo " . str . "%4294967296" . " \| bc " . preload)
            let answer2 = system ("echo obase=16 ;" . str . "/4294967296" . " \| bc " . preload)
            let answer3 = system ("echo obase=16 ;" . str . "%4294967296" . " \| bc " . preload)
        endif
        let answer = "scn_wrap,scn_base(10): " . answer . "," . answer1 . " = scn_wrap,scn_base(16): " . "0x" . tolower (answer2) . "," . "0x" . tolower(answer3)
    endif

    if a:flag == 10016
        if has_hex == 1
            let str = toupper (str)
            let str = substitute (str, "0x", "", "g")
            " 0x100000000 hexdecimal = 4294967296(10) = 2^32(10)
            let str = substitute (str, "[,.]", "*100000000+", "g")
            let answer  = system ("echo obase=10 ;ibase=16 ;" . str .  " \| bc -l " . preload)
            let answer1 = system ("echo obase=16 ;ibase=16 ;" . str .  " \| bc -l " . preload)
        else
            let str = substitute (str, "[,.]", "*4294967296+", "g")
            let answer  = system ("echo " . str . " \| bc -l " . preload)
            let answer1 = system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
        endif
        let answer = "scn(10): " . answer . " = scn(16): " . "0x" . tolower (answer1)
    endif

    if a:flag == 20016
        if has_hex == 1
            let str = toupper ( str )
            let str = substitute (str, "0x", "", "g")
            " 0x400000 hexdecimal = 4194304 (10) = 2^22(10)
            let str = substitute (str, "[,.]", "*400000+", "g")
            let answer  = system ("echo obase=10 ;ibase=16 ;" . str .  " \| bc -l " . preload)
            let answer1 = system ("echo obase=16 ;ibase=16 ;" . str .  " \| bc -l " . preload)
        else
            let str = substitute (str, "[,.]", "*4194304+", "g")
            let answer  = system ("echo " . str . " \| bc -l " . preload)
            let answer1 = system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
        endif
        let answer = "file#,block# dba(10): " . answer . " = file#,block# dba(16): " . "0x" . tolower (answer1)
    endif

    if a:flag == 30016
        if has_hex == 1
            let str = substitute (str, "0x", "", "g")
            let str = toupper ( str )
            let answer = system ("echo ibase=16 ;" . str .  " \| bc -l " . preload)
        else
            let answer = system ("echo obase=16 ;" . str .  " \| bc -l " . preload)
            let answer = "0x" . tolower ( answer )
        endif
    endif

    " strip newline and \
    let answer = substitute (answer, "[\\\n]", "", "g")

    " strip trailing 0s in decimals
    let answer = substitute (answer, '\.\(\d*[1-9]\)0\+$', '.\1', "")
    let answer = substitute (answer, '\.0\+$', '', "")

    return answer
endfunction

" ---------------------------------------------------------------------
" CalcLines:
"
" take expression from lines, either visually selected or the current line,
" pass to calculate function, echo or past answer after '='
function! CalcLines(flag)

    let has_equal = 0

    " remove newlines and trailing spaces
    let @e = substitute (@e, "\n", "",   "g")
    let @e = substitute (@e, '\s*$', "", "g")

    " if we end with an equal, strip, and remember for output
    if @e =~ "=$"
        let @e = substitute (@e, '=$', "", "")
        let has_equal = 1
    endif

    " if there is another equal in the line, assume chained equations, remove
    " leading ones
    let @e = substitute (@e, '^.\+=', '', '')

    let answer = Calculate (@e,a:flag)

    " append answer or echo
    if has_equal == 1
        exec "normal a" . answer
    else
        echo "answer = " . answer
    endif
endfunction

" ---------------------------------------------------------------------
" Check_hex:
"
" Check if the string contains 0x, a, b, c, d, e, f  return has_hex=1
function! Check_hex(str)
    let has_hex = 0
    let ss = a:str
    let ss = tolower ( ss )

    if ss =~ "0x"
        let has_hex = 1
        return has_hex
    endif

    if ss =~ "[abcdef]"
        let has_hex = 1
        return has_hex
    endif

endfunction


您的分享是我們最大的動力!

-Advertisement-
Play Games
更多相關文章
  • 1. 問題背景 現在我們兩套語言並行,其中必然會涉及到不同系統的相互訪問。 .net 的會員信息是用 webservice 提供服務的。那如何對現有 .net webservice 不做任何改動的情況下,用 Java 的 cxf 來訪問呢,公司的知識庫裡面也有這個技術專題,但是我們公司招投標的 .n ...
  • Aspose.Slides for .NET是一個獨特的演示處理API,它允許應用程式讀取、寫入、修改和轉換PowerPoint演示文稿。作為一個獨立的API,它提供了管理PowerPoint關鍵功能的功能,如管理文本、形狀、表格和動畫、向幻燈片添加音頻和視頻、預覽幻燈片等,而不需要Microsof ...
  • 在我們實際開發報表的時候,我們需要按一定的業務規則組織好報表的模板設計,讓報表儘可能的貼近實際的需求,在之前的隨筆中《使用FastReport報表工具生成報表PDF文檔》介紹了FastReport生成常規報表的處理,本篇隨筆回顧常規報表的處理效果,並介紹基於FastReport生成標簽紙列印需要的報... ...
  • 記得做這個框架是在2018年剛接觸.net core的時候,那個時候為了能夠專心的研究我開始不寫博客了,在公司運用了近一年的時間了,決定回來和各位分享我們所掌握的那星星點點的知識,希望可以幫助更多的開發人員找到更完善的解決方案,有不足的地方歡迎各位指教。好,那麼我們來說說這個日誌框架。 開發緣由 那 ...
  • 場景 DataGridView怎樣實現添加、刪除、上移、下移一行: https://blog.csdn.net/BADAO_LIUMANG_QIZHI/article/details/102814145 註: 博客主頁: https://blog.csdn.net/badao_liumang_qiz ...
  • 場景 在Winform中使用DataGridView實現添加一行、刪除一行、上移一行、下移一行。 註: 博客主頁: https://blog.csdn.net/badao_liumang_qizhi 關註公眾號 霸道的程式猿 獲取編程相關電子書、教程推送與免費下載。 實現 添加一行 效果 刪除一行 ...
  • 為了呼應《中國.NET開發者峰會2019上海站》,作為演講嘉賓,我希望和各位同行建立更多的互動,為此,我特地將部分演講內容,整理成文章先行發佈。 ...
  • 1. 前言 最近常常接觸到GetAlphaMask,所以想寫這篇文章介紹下GetAlphaMask怎麼使用。其實GetAlphaMask的使用場景十分有限,Github上能搜到的內容都是用來配合DropShadow的,所以這篇文章也以介紹DropShadow為主。 2. 合成陰影 先介紹一下合成陰影 ...
一周排行
    -Advertisement-
    Play Games
  • 移動開發(一):使用.NET MAUI開發第一個安卓APP 對於工作多年的C#程式員來說,近來想嘗試開發一款安卓APP,考慮了很久最終選擇使用.NET MAUI這個微軟官方的框架來嘗試體驗開發安卓APP,畢竟是使用Visual Studio開發工具,使用起來也比較的順手,結合微軟官方的教程進行了安卓 ...
  • 前言 QuestPDF 是一個開源 .NET 庫,用於生成 PDF 文檔。使用了C# Fluent API方式可簡化開發、減少錯誤並提高工作效率。利用它可以輕鬆生成 PDF 報告、發票、導出文件等。 項目介紹 QuestPDF 是一個革命性的開源 .NET 庫,它徹底改變了我們生成 PDF 文檔的方 ...
  • 項目地址 項目後端地址: https://github.com/ZyPLJ/ZYTteeHole 項目前端頁面地址: ZyPLJ/TreeHoleVue (github.com) https://github.com/ZyPLJ/TreeHoleVue 目前項目測試訪問地址: http://tree ...
  • 話不多說,直接開乾 一.下載 1.官方鏈接下載: https://www.microsoft.com/zh-cn/sql-server/sql-server-downloads 2.在下載目錄中找到下麵這個小的安裝包 SQL2022-SSEI-Dev.exe,運行開始下載SQL server; 二. ...
  • 前言 隨著物聯網(IoT)技術的迅猛發展,MQTT(消息隊列遙測傳輸)協議憑藉其輕量級和高效性,已成為眾多物聯網應用的首選通信標準。 MQTTnet 作為一個高性能的 .NET 開源庫,為 .NET 平臺上的 MQTT 客戶端與伺服器開發提供了強大的支持。 本文將全面介紹 MQTTnet 的核心功能 ...
  • Serilog支持多種接收器用於日誌存儲,增強器用於添加屬性,LogContext管理動態屬性,支持多種輸出格式包括純文本、JSON及ExpressionTemplate。還提供了自定義格式化選項,適用於不同需求。 ...
  • 目錄簡介獲取 HTML 文檔解析 HTML 文檔測試參考文章 簡介 動態內容網站使用 JavaScript 腳本動態檢索和渲染數據,爬取信息時需要模擬瀏覽器行為,否則獲取到的源碼基本是空的。 本文使用的爬取步驟如下: 使用 Selenium 獲取渲染後的 HTML 文檔 使用 HtmlAgility ...
  • 1.前言 什麼是熱更新 游戲或者軟體更新時,無需重新下載客戶端進行安裝,而是在應用程式啟動的情況下,在內部進行資源或者代碼更新 Unity目前常用熱更新解決方案 HybridCLR,Xlua,ILRuntime等 Unity目前常用資源管理解決方案 AssetBundles,Addressable, ...
  • 本文章主要是在C# ASP.NET Core Web API框架實現向手機發送驗證碼簡訊功能。這裡我選擇是一個互億無線簡訊驗證碼平臺,其實像阿裡雲,騰訊雲上面也可以。 首先我們先去 互億無線 https://www.ihuyi.com/api/sms.html 去註冊一個賬號 註冊完成賬號後,它會送 ...
  • 通過以下方式可以高效,並保證數據同步的可靠性 1.API設計 使用RESTful設計,確保API端點明確,並使用適當的HTTP方法(如POST用於創建,PUT用於更新)。 設計清晰的請求和響應模型,以確保客戶端能夠理解預期格式。 2.數據驗證 在伺服器端進行嚴格的數據驗證,確保接收到的數據符合預期格 ...