JS數組去重的十種方法

来源:http://www.cnblogs.com/yuanbo88/archive/2017/08/11/7345331.html
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一、前言： 我們在實際工作中，或者在面試找工作時，都會用到或者被問到一個問題，那就是“數組如何去重”。是的，這個問題有很多種解決方案，看看下麵的十種方式吧！ 二、數組去重方式大彙總： Methods 1: 思路：定義一個新數組，並存放原數組的第一個元素，然後將元素組一一和新數組的元素對比，若不同則存 ...


一、前言：

我們在實際工作中，或者在面試找工作時，都會用到或者被問到一個問題，那就是“數組如何去重”。是的，這個問題有很多種解決方案，看看下麵的十種方式吧！

 

二、數組去重方式大彙總：

Methods 1: 思路：定義一個新數組，並存放原數組的第一個元素，然後將元素組一一和新數組的元素對比，若不同則存放在新數組中。

		function unique(arr){
			var res = [arr[0]];
			for(var i=1; i<arr.length; i++){
				var repeat = false;
				for(var j=0; j<res.length; j++){
					if(arr[i] === res[j]){
						repeat = true;
						break;
					}
				}

				if(!repeat){
					res.push(arr[i]);
				}
			}
			return res;
		}
		console.log('------------方法一---------------');
		console.log(unique([1,1,2,3,5,3,1,5,6,7,4]));

Methods 2: 思路：先將原數組排序，在與相鄰的進行比較，如果不同則存入新數組。

		function unique2(arr){
			var arr2 = arr.sort();
			var res = [arr2[0]];
			for(var i=1; i<arr2.length; i++){
				if(arr2[i] !== res[res.length-1]){
					res.push(arr2[i]);
				}
			}

			return res;
		}
		console.log('------------方法二---------------');
		console.log(unique2([1,1,2,3,5,3,1,5,6,7,4]));

Methods 3: 利用對象屬性存在的特性，如果沒有該屬性則存入新數組。

		function unique3(arr){
			var res = [];
			var obj = {};
			for(var i=0; i<arr.length; i++){
				if( !obj[arr[i]] ){
					obj[arr[i]] = 1;
					res.push(arr[i]);
				}
			}

			return res;
		}
		console.log('------------方法三---------------');
		console.log(unique3([1,1,2,3,5,3,1,5,6,7,4]));

Methods 4: 利用數組的indexOf下標屬性來查詢。

		function unique4(arr){
			var res = [];
			for(var i=0; i<arr.length; i++){
				if(res.indexOf(arr[i]) == -1){
					res.push(arr[i]);
				}
			}

			return res;
		}
		console.log('------------方法四---------------');
		console.log(unique4([1,1,2,3,5,3,1,5,6,7,4]));

Methods 5: 利用數組原型對象上的includes方法。

		function unique5(arr){
			var res = [];

			for(var i=0; i<arr.length; i++){
				if( !res.includes(arr[i]) ){ // 如果res新數組包含當前迴圈item
					res.push(arr[i]);
				}
			}

			return res;
		}
		console.log('------------方法五---------------');
		console.log(unique5([1,1,2,3,5,3,1,5,6,7,4]));

Methods 6: 利用數組原型對象上的 filter 和 includes方法。

		function unique6(arr){
			var res = [];

			res = arr.filter(function(item){
			  return res.includes(item) ? '' : res.push(item);
			});

			return res;
		}
		console.log('------------方法六---------------');
		console.log(unique6([1,1,2,3,5,3,1,5,6,7,4]));

Methods 7: 利用數組原型對象上的 forEach 和 includes方法。

		function unique7(arr){
			var res = [];

			arr.forEach(function(item){
			  res.includes(item) ? '' : res.push(item);
			});

			return res;
		}
		console.log('------------方法七---------------');
		console.log(unique7([1,1,2,3,5,3,1,5,6,7,4]));

Methods 8: 利用數組原型對象上的 splice 方法。

		function unique8(arr){
			var i,
				j,
				len = arr.length;

			for(i = 0; i < len; i++){
		        for(j = i + 1; j < len; j++){
		            if(arr[i] == arr[j]){
		                arr.splice(j,1);
		                len--;
		                j--;
		            }
		        }
		    }

			return arr;
		}
		console.log('------------方法八---------------');
		console.log(unique8([1,1,2,3,5,3,1,5,6,7,4]));

Methods 9: 利用數組原型對象上的 lastIndexOf 方法。

		function unique9(arr){
			var res = [];

			for(var i=0; i<arr.length; i++){
				res.lastIndexOf(arr[i]) !== -1 ? '' : res.push(arr[i]);
			}

			return res;
		}
		console.log('------------方法九---------------');
		console.log(unique9([1,1,2,3,5,3,1,5,6,7,4]));

Methods 10: 利用 ES6的set 方法。

		function unique10(arr){
			//Set數據結構，它類似於數組，其成員的值都是唯一的
			return Array.from(new Set(arr)); // 利用Array.from將Set結構轉換成數組
		}
		console.log('------------方法十---------------');
		console.log(unique10([1,1,2,3,5,3,1,5,6,7,4]));

 

三、其他：

有意思的是，當我把數組的長度變得很大的時候（如下所示），測試了一下不同方法的執行時間長短，會發現方法三、四、五、六、七相對來說會更有優勢，而方法八的執行速度似乎一直墊底。你也可以在你本地跑一下試試！

	//測試用的超大數組
	var arr = 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	//這裡只是舉例方法三（如果你把所有方法放在一起測試，會更直觀的看到執行時間的差異）
	var time3 = new Date().getTime();
	function unique3(arr){
		var res = [];
		var obj = {};
		for(var i=0; i<arr.length; i++){
			if( !obj[arr[i]] ){
				obj[arr[i]] = 1;
				res.push(arr[i]);
			}
		}

		return res;
	}
	console.log('------------方法三---------------');
	console.log( unique3(arr) );
	console.log('3所花時間： ' + (new Date().getTime() - time3));

 


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