Python騷操作來了~

用Python來實現科目一/四自動答題，100分不要太簡單！

最初是表弟最近想買車，但是駕照都沒有，買什麼車，只能先考駕照~

看他在網頁上練習題目慢吞吞的，我就看不下去了，直接給他來一手揠苗助長~

當時就用Python整了幾十行代碼，給他實現一下自動答題，我說你什麼時候答題這麼快，我就給你買個車！

嘿嘿，悄悄告訴你們，那是不可能的，不信你們看案例演示！

案例效果演示

就這速度，我可沒加速哈~

代碼展示

代碼僅做展示

網址我屏蔽了，不然系統不給過~

模塊

import requests
import parsel
from selenium import webdriver

發送請求

def get_response(html_url):
    """
    :param html_url: 請求網址
    :return: 響應對象
    """
    headers = {
        'user-agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.0.0 Safari/537.36'
    }
    response = requests.get(url=html_url, headers=headers)
    return response

獲取答案鏈接

def get_answer_url(html_url):
    """
    :param html_url:
    :return:
    """
    html_data = get_response(html_url).text
    selector = parsel.Selector(html_data)
    answer_url_id = selector.css('.Content li::attr(c)').getall()
    answer_url_list = [f'https://地址我屏蔽了，不然不給過/Post/{i}.htm' for i in answer_url_id]
    return answer_url_list

獲取答案

def get_answer_result(answer_url):
    """
    
    :param answer_url:
    :return:
    """
    answer_data = get_response(html_url=answer_url).text
    selector = parsel.Selector(answer_data)
    question = selector.css('#question a::text').get()
    answer = selector.css('#question h1 u::text').get()
    if answer == '對':
        answer = '正確'
    elif answer == '錯':
        answer = '錯誤'

    answer_dict = {
        '問題': question,
        '答案': answer
    }
    return answer_dict

獲取所有問題以及答案

def get_all_answer(answer_url_list):
    """
    完整源碼都放在這個裙了 279199867
    :param link:
    :return:
    """
    page = 1
    for answer_url, li in zip(answer_url_list, lis):
        answer_dict = get_answer_result(answer_url)
        bs = li.find_elements_by_css_selector('b')
        num = 1
        for b in bs:
            choose = b.text
            if len(choose) > 2:
                choose = choose[0]
            print(choose, answer_dict['答案'])
            if choose in answer_dict['答案']:
                driver.find_element_by_css_selector(f'#LI{page} b:nth-child({num+2})').click()
                print('點擊了')
            else:
                print('沒有點擊')
            num += 1
        page += 1
        print(answer_dict)

完整源代碼下方名片獲取哈~

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