實驗9：Problem E: 點在圓內嗎？

有個坑是：

1. The Point (0, 0) is created!
2. A Point (0, 0) is copied!
3.  A Point (0, 0) is erased!

Description

定義一個Point類和Circle類，用於判斷給定的一系列的點是否在給定的圓內。

其中，Point類：

1.有2個成員x和y，分別為其橫坐標和縱坐標；1個靜態成員numOfPoints，用於計算生成的點的個數。

2.具有構造函數、析構函數和拷貝構造函數，具體格式輸出根據樣例自行判斷。

3. 具有靜態方法int getNumOfPoints()，用於返回numOfPoints的值。

4. 具有int getX()和int getY()方法，用於獲取橫坐標和縱坐標。

Circle類：

1. 擁有Point類的對象center，表示圓心坐標。擁有radius對象，表示圓的半徑；1個靜態成員numOfCircles，用於指示生成了多少個圓對象。

2. 具有構造函數、析構函數和拷貝構造函數，具體格式根據樣例自行判斷。

3.具有靜態方法int getNumOfCircles()，返回numOfCircles的值。

4. 具有getCenter()方法，返回圓心坐標。註意：根據輸出結果判斷返回值類型。

5. 具有bool pointInCircle(Point &)方法，用於判斷給定的點是否在當前圓內。是則返回true，否則返回false。

Input

輸入分多行。

第一行M>0，表示有M個測試用例。

每個測試用例又包括多行。第1行包含3個整數，分別為一個圓的橫坐標、縱坐標和半徑。第2行N>0，表示之後又N個點，每個點占一行，分別為其橫坐標和縱坐標。

所有輸入均為整數，且在int類型範圍內。

Output

輸出見樣例。註意：在圓的邊上的點，不在圓內。

Sample Input

Sample Output

HINT

Append Code

#include<iostream>
using namespace std;
class Point{
public:
    int x,y;
    static int numOfPoints;
    Point(int a=0,int b=0):x(a),y(b){numOfPoints++;cout<<"The Point ("<<x<<", "<<y<<") is created! Now, we have "<<numOfPoints<<" points."<<endl;}
    ~Point(){numOfPoints--;cout<<"A Point ("<<x<<", "<<y<<") is erased! Now, we have "<<numOfPoints<<" points."<<endl;}
    Point(const Point&p){numOfPoints++;x=p.x;y=p.y;cout<<"A Point ("<<x<<", "<<y<<") is copied! Now, we have "<<numOfPoints<<" points."<<endl;}
    static int getNumOfPoints(){return numOfPoints;}
    int getX(){return x;}
    int getY(){return y;}

};
class Circle{
public:
    Point center;
    int radius;
    static int numOfCircles;
    Circle(int a,int b,int c):center(a,b),radius(c){numOfCircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    Circle(Point p,int r):center(p),radius(r){numOfCircles++;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    ~Circle(){numOfCircles--;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is erased! Now, we have "<<numOfCircles<<" circles."<<endl;}
    Circle(const Circle &c){numOfCircles++;center.x=c.center.x;center.y=c.center.y;radius=c.radius;cout<<"A circle at ("<<center.x<<", "<<center.y<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles."<<endl;}
    static int getNumOfCircles(){return numOfCircles;}
    Point &getCenter(){return center;}
    bool pointInCircle(Point &p){if((p.x-center.x)*(p.x-center.x)+(p.y-center.y)*(p.y-center.y)<radius*radius) return true;else return false;}
};
int Point::numOfPoints=0;
int Circle::numOfCircles=0;
int main()
{
    int cases,num;
    int x, y, r, px, py;
    Point aPoint(0,0), *bPoint;
    Circle aCircle(1,1,1);
    cin>>cases;
    cout<<"We have "<<Point::getNumOfPoints()<<" points and "<<Circle::getNumOfCircles()<<" circles now."<<endl;
    for (int i = 0; i < cases; i++)
    {
        cin>>x>>y>>r;
        bPoint = new Point(x,y);
        Circle circle(*bPoint, r);
        cin>>num;
        for (int j = 0; j < num; j++)
        {
            cin>>px>>py;
            if (circle.pointInCircle(*(new Point(px, py))))
            {
                cout<<"("<<px<<", "<<py<<") is in the circle at (";
                cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
            }
            else
            {
                cout<<"("<<px<<", "<<py<<") is not in the circle at (";
                cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
            }
        }
        delete bPoint;
    }
    cout<<"We have "<<Point::getNumOfPoints()<<" points, and "<<Circle::getNumOfCircles()<<" circles."<<endl;
    return 0;
}