資料庫拼接表

這是一道面試題，覺得有點意思就發出來了。

1。如圖兩個表,上為A,下為R

一、效果一

二、效果二

三、效果三

CREATE DATABASE AR GO USE AR go CREATE TABLE A (  code INT PRIMARY KEY NOT NULL,  Area VARCHAR(20) ) INSERT INTO a VALUES(1,'A1') INSERT INTO a VALUES(2,'A2') INSERT INTO a VALUES(3,'A3') INSERT INTO a VALUES(5,'') INSERT INTO a VALUES(7,'') CREATE TABLE R (  code INT PRIMARY KEY NOT NULL,  Area VARCHAR(20) ) INSERT INTO r VALUES(1,'R1') INSERT INTO r VALUES(3,'R3') INSERT INTO r VALUES(6,'') INSERT INTO r VALUES(8,'')

--1 select * from A union select * from R order by code

--2 select identity(int,1,1) as guid,code,Area into #1 from A select identity(int,1,1) as guid,code,Area into #2 from R select a.code as code1,a.Area as Area1,b.code as code2,b.Area as Area2 into #3 from #1 a inner join #2 b on a.guid = b.guid select * from #3

--3 select identity(int,1,1) as guid,code,Area into #1 from A select identity(int,1,1) as guid,code,Area into #2 from R select a.code as code1,a.Area as Area1,b.code as code2,b.Area as Area2 into #3 from #1 a right join #2 b on a.guid = b.guid select * from #3

--1 SELECT * FROM a UNION SELECT * FROM r

--2 SELECT m.code AS code1,m.Area AS area1,n.code AS code2,n.Area AS area2 FROM  (SELECT * ,(SELECT COUNT(*)+1 FROM a a1 WHERE a1.code<a2.code) AS id FROM a a2 ) m  join  (SELECT * ,(SELECT COUNT(*)+1 FROM r r1 WHERE r1.code<r2.code) AS id FROM R r2) n  on m.id=n.id

 --3  SELECT m.code AS code1,m.Area AS area1,n.code AS code2,n.Area AS area2 FROM  (SELECT * ,(SELECT COUNT(*)+1 FROM a a1 WHERE a1.code<a2.code) AS id FROM a a2 ) m  LEFT join  (SELECT * ,(SELECT COUNT(*)+1 FROM r r1 WHERE r1.code<r2.code) AS id FROM R r2) n  on m.id=n.id