C Primer Plus (7.12) 編程練習

来源:https://www.cnblogs.com/NoldorFromMiddleEarth/archive/2023/02/03/17087833.html
-Advertisement-
Play Games

/*C Primer Plus (7.11) 3*/ 1 #include<stdio.h> 2 int main() 3 { 4 double weight,height; 5 printf("Please enter your weight and height.\n"); 6 printf(" ...


/*C Primer Plus (7.11) 3*/

 1 #include<stdio.h>
 2 int main()
 3 {
 4     double weight,height;
 5     printf("Please enter your weight and height.\n");
 6     printf("Weight (pound):");
 7     scanf("%lf",&weight);
 8     printf("Height (inch):");
 9     scanf("%lf",&height);
10 //加入建立比較友好的人機交互
11     if (weight < 100 && height > 64)
12         if (height >= 72)
13         printf("You are very tall for your weight.\n");
14     else
15         printf("You are tall for your weight.\n");
16     else if (weight > 300 && height < 48)
17         printf("You are quite short for your weight.\n");
18     else
19         printf("Your weight is ideal.\n");
20 //減少沒有用的if判斷條件
21     return 0;
22 }
23 /*
24 輸出樣例
25 
26 Please enter your weight and height.
27 Weight (pound):99
28 Height (inch):65
29 You are tall for your weight.
30 
31 Please enter your weight and height.
32 Weight (pound):98
33 Height (inch):72
34 You are very tall for your weight.
35 
36 Please enter your weight and height.
37 Weight (pound):301
38 Height (inch):46
39 You are quite short for your weight.
40 
41 Please enter your weight and height.
42 Weight (pound):200
43 Height (inch):50
44 Your weight is ideal.
45 
46 */

/*C Primer Plus (7.11) 10*/

 1 #include<stdio.h>
 2 int main()
 3 {
 4     char ch;
 5 
 6     while ((ch=getchar()) != '#')
 7     {
 8         if (ch != '\n')
 9         {
10             printf("Step 1\n");
11             if (ch == 'b')
12                 break;
13             else if (ch !='c')
14             {
15                 if (ch != 'h')
16                     printf("Step 2\n");
17                     printf("Step 3\n");
18             }
19         }
20     }
21     printf("Done.\n");
22     return 0;
23 }
24 /*
25 輸出樣例
26 
27 q
28 Step 1
29 Step 2
30 Step 3
31 c
32 Step 1
33 h
34 Step 1
35 Step 3
36 b
37 Step 1
38 Done.
39 
40 */

/*C Primer Plus (7.12) 1*/

 1 #include<stdio.h>
 2 int main()
 3 {
 4     int space, linebreak, others;
 5     int realothers = 0;
 6     char ch;
 7     space = linebreak = others = 0;
 8 
 9     printf("Please enter some characters (# to quit).\n");
10     while ((ch = getchar()) != '#')
11     {
12         if (ch == ' ' ? space++ : others++ && ch == '\n' ? linebreak++ : others++);
13     }
14     realothers = others / 2;
15     printf("These are the number of characters required for statistics.\n");
16     printf("Space : %d" ,space);
17     printf("\nLinebreak : %d" ,linebreak);
18     printf("\nOthers: %d" ,realothers);
19 
20     return 0;
21 }
22 /*
23 輸出樣例
24 
25 Please enter some characters (# to quit).
26 Hello,My name is Coco.
27 Hello. My name is Mike !#
28 These are the number of characters required for statistics.
29 Space : 8
30 Linebreak : 1
31 Others: 38
32 
33 */

/*C Primer Plus (7.12) 2*/

 1 #include<stdio.h>
 2 int main(void)
 3 {
 4     int i = 0;
 5     char ch;
 6 
 7     printf("Please enter some characters (# to quit):");
 8     while ((ch = getchar()) != '#')
 9     {
10         if (i++ % 8 == 0)
11         {
12             putchar('\n');                     //每輸出8個字元的信息就進行一次換行操作
13         }
14         if (ch == '\n')
15         {
16             printf("\'\\n\' -> %2d ",ch);
17         }
18         else if (ch == '\t')
19         {
20             printf("\'\\t\' -> %2d ",ch);
21         }
22         else
23         {
24             printf("\'%c\' -> %2d ",ch,ch);
25         }
26     }
27     printf("\nDone.");
28 
29     return 0;
30 }
31 /*
32 輸出樣例
33 
34 Please enter some characters (# to quit):KurokiTomoko#
35 
36 'K' -> 75 'u' -> 117 'r' -> 114 'o' -> 111 'k' -> 107 'i' -> 105 'T' -> 84 'o' -> 111
37 'm' -> 109 'o' -> 111 'k' -> 107 'o' -> 111
38 Done.
39 
40 */

/*C Primer Plus (7.12) 3*/

 1 #include<stdio.h>
 2 int main()
 3 {
 4     int num;
 5     int even,odd;                    //偶數的個數,奇數的個數
 6     int e_sum,o_sum;
 7     double e_value,o_value;          //偶數和的平均值,奇數和的平均值
 8     even = odd = num = e_sum = o_sum = 0;
 9     e_value = o_value =0.0;
10     printf("Please enter some integer numbers.\n");
11     printf("The result your entered (0 to quit) : ");
12     while (scanf("%d",&num) == 1 && num)
13     {
14         (num % 2 == 0 ? (even++, e_sum += num) : (odd++, o_sum += num));
15         printf("Now you can enter again (0 to quit) : ");
16     }
17     printf("There are %d even numbers.\n",even);
18     if (even > 0)
19     {
20         e_value = e_sum / (double)even;
21         printf("The average of even numbers is : %.3lf\n",e_value);
22     }
23     printf("There are %d odd numbers.\n",odd);
24     if (odd > 0)
25     {
26         o_value = o_sum / (double)odd;
27         printf("The average of odd numbers is : %.3lf",o_value);
28     }
29     printf("\nDone.");
30     return 0;
31 }
32 /*
33 輸出樣例
34 
35 Please enter some integer numbers.
36 The result your entered (0 to quit) : 1
37 Now you can enter again (0 to quit) : 2
38 Now you can enter again (0 to quit) : 3
39 Now you can enter again (0 to quit) : 4
40 Now you can enter again (0 to quit) : 5
41 Now you can enter again (0 to quit) : 6
42 Now you can enter again (0 to quit) : 7
43 Now you can enter again (0 to quit) : 8
44 Now you can enter again (0 to quit) : 9
45 Now you can enter again (0 to quit) : 0
46 There are 4 even numbers.
47 The average of even numbers is : 5.000
48 There are 5 odd numbers.
49 The average of odd numbers is : 5.000
50 Done.
51 
52 */

/*C Primer Plus (7.12) 4*/

 1 #include<stdio.h>
 2 int main()
 3 {
 4     char ch;
 5     int count1 = 0;
 6     int count2 = 0;
 7     printf("Please enter the text you want (enter '#' to quit).");
 8     printf("\nNow please enter : ");
 9     while ((ch = getchar()) != '#')
10     {
11         if (ch == '.')
12         {
13             putchar('!');
14             count1++;
15         }
16         else if (ch == '!')
17         {
18             printf("!!");
19             count2++;
20         }
21         else
22         {
23             putchar(ch);
24         }
25     }
26     printf("The number of times an exclamation mark "
27            "has been replaced with a period is : %d",count1);
28     printf("\nThe number of times an exclamation mark "
29            "is replaced by two exclamations is : %d",count2);
30     printf("\nDone.");
31 
32     return 0;
33 }
34 /*
35 輸出樣例
36 
37 Please enter the text you want (enter '#' to quit).
38 Now please enter : !!!!!.....
39 !!!!!!!!!!!!!!!
40 #
41 The number of times an exclamation mark has been replaced with a period is : 5
42 The number of times an exclamation mark is replaced by two exclamations is : 5
43 Done.
44 
45 */

/*C Primer Plus (7.12) 5*/

#include<stdio.h>
int main()
{
    char ch;
    int count1 = 0;
    int count2 = 0;
    printf("Please enter the text you want (enter '#' to quit).");
    printf("\nNow please enter : ");
    while ((ch = getchar()) != '#')
    {
        switch(ch)
        {
        case '.':
            {
                putchar('!');
                count1++;
                break;
            }
        case '!':
            {
                printf("!!");
                count2++;
                break;
            }
        default:
            {
                putchar(ch);
            }
        }
    }
    printf("The number of times an exclamation mark "
           "has been replaced with a period is : %d",count1);
    printf("\nThe number of times an exclamation mark "
           "is replaced by two exclamations is : %d",count2);
    printf("\nDone.");

    return 0;
}
/*
輸出樣例

Please enter the text you want (enter '#' to quit).
Now please enter : Hello, This is Coconut !
Hello, This is Coconut !!
My name is Coconut.
My name is Coconut!
#
The number of times an exclamation mark has been replaced with a period is : 1
The number of times an exclamation mark is replaced by two exclamations is : 1
Done.

*/

/*C Primer Plus (7.12) 6*/

#include<stdio.h>
int main()
{
    int count = 0;
    char ch;
    char prev;            //讀取的前一個字元
    printf("Please enter some characters ('#' to quit):");
    prev = '#';          //前一個字元為“#”的時候會停止(用於識別結束符號)
    while ((ch = getchar()) != '#')
    {
        if(prev == 'e' && ch == 'i')
            count++;
        prev = ch;
    }
    printf("There %d ei in this sentence.",count);

    return 0;
}
/*
輸出樣例

Please enter some characters ('#' to quit):Receive your eieio award.#
There 3 ei in this sentence.

*/

/*C Primer Plus (7.12) 7*/

#include<stdio.h>
#define BASIC_SALARY 10.00
#define EXTRA_WORK 1.5
#define NORMAL_TAX 0.15
#define EXTRA_TAX 0.20
#define OTHER_TAX 0.25
int main()
{
    double worktime = 0.0;
    double salary,tax,netincome;
    salary = tax = netincome = 0.0;
    printf("Please enter your "
           "working hours in a week : ");
    while (scanf("%lf",&worktime) != 1 || worktime <= 0)
    {
        while (getchar() != '\n') continue;
        printf("Please enter a right number( >= 0 ).");
    }
    salary = worktime > 40 ? (40.00 * BASIC_SALARY) + (1.5 * (worktime - 40)) * BASIC_SALARY : worktime * BASIC_SALARY;
    if (salary <= 300)
    {
        tax = 300.00 * NORMAL_TAX;
        netincome = salary - tax;
    }
    else if (salary <= 450)
    {
        tax = 300.00 * NORMAL_TAX + (salary - 300.00) * EXTRA_TAX;
        netincome = salary - tax;
    }
    else
    {
        tax = 300.00 * NORMAL_TAX + 150.00 * EXTRA_TAX + (salary - 450.00) * OTHER_TAX;
        netincome = salary - tax;
    }
    printf("There is your salary, tax and net income information.\n");
    printf("Salary : %.3lf",salary);
    printf("\nTax : %.3lf",tax);
    printf("\nNet income : %.3lf",netincome);

    return 0;
}
/*
輸出樣例

Please enter your working hours in a week : 300
There is your salary, tax and net income information.
Salary : 4300.000
Tax : 1037.500
Net income : 3262.500

Please enter your working hours in a week : 450
There is your salary, tax and net income information.
Salary : 6550.000
Tax : 1600.000
Net income : 4950.000

Please enter your working hours in a week : 521.73
There is your salary, tax and net income information.
Salary : 7625.950
Tax : 1868.988
Net income : 5756.963
*/

/*C Primer Plus (7.12) 8*/

#include<stdio.h>
#include<stdbool.h>
#define EXTRA_WORK 1.5
#define NORMAL_TAX 0.15
#define EXTRA_TAX 0.20
#define OTHER_TAX 0.25
void quit ();
void menu ();
void Salary (double Bsalary , double worktime);

int choice = 0;
double worktime = 0.0;

int main()
{
    while (true)
    {
         menu ();

         switch(choice)
     {
        case 1 :
           {
               Salary(8.75,worktime);
               break;
           }
        case 2 :
           {
               Salary(9.33,worktime);
               break;
           }
        case 3 :
           {
               Salary(10.00,worktime);
               break;
           }
        case 4 :
           {
               Salary(11.20,worktime);
               break;
           }
        case 5 :
           {
               quit();
               printf("Done.");
               return 0;
           }
     }
    }
}

void quit()
{
    printf("\t\t\n************************************************\t\t\n");
    printf("||                                            ||");
    printf("\n||                                            ||");
    printf("\n||      Thank you to use this programme!      ||");
    printf("\n||                                            ||");
    printf("\n||                                            ||");
    printf("\t\t\n************************************************\t\t\n");
}

void menu()
{
    printf("\t\t\n*****************************************************************\t\t\n");
    printf("Enter the number corresponding to the desired pay rate or action:\n");
    printf("1) $8.75/hr                          2) $9.33/hr");
    printf("\n3) $10.00/hr                         4) $11.20/hr\n");
    printf("5) quit");
    printf("\t\t\n*****************************************************************\t\t\n");
    printf("Please enter your options: ");
    scanf("%d",&choice);
    while (choice != 1 && choice != 2 && choice != 3 && choice != 4 && choice != 5)
    {
        printf("Please enter the right choice:");
        scanf("%d",&choice);
    }
}

void Salary(double Bsalary , double worktime)
{
  double tax,netincome,salary;
  salary = tax = netincome = 0.0;
  printf("Please enter your working hours in a week : ");

    while (scanf("%lf",&worktime) != 1 || worktime <= 0)
    {
        while (getchar() != '\n') continue;
        printf("Please enter a right number( >= 0 ).	   

您的分享是我們最大的動力!

-Advertisement-
Play Games
更多相關文章
  • 1:apk文件結構 如圖所示: assets: 存放應用程式的靜態資源文件,如圖片資源,json配置文件,html離線資源等。註意,assets目錄下是支持任意深度的子目錄。 res: 規定的指定文件,圖標,圖片資源等,且res下文件都會生成對應的資源id, 但是assets下是不會的。 lib: ...
  • 在元素設置浮動(float)後,該元素就會脫離文檔流,並且向左或向右浮動,直至它的外邊緣遇到包含框或者另一個浮動框的邊緣。 一、浮動元素對佈局的影響 1.1、浮動元素造成父元素的高度塌陷: 原來的父元素高度是內部元素撐開的,但是當內部元素浮動後,脫離文檔流浮動起來,那父元素的高度就坍塌,變為高度 0 ...
  • 寫代碼的時候遇到這個問題了,在這裡複習一下 非箭頭函數 非箭頭函數的this指向比較好理解,就是調用這個函數的對象,舉個慄子: var obj = { foo: { bar: 3, foo:{ bar: 4, foo: function a() { console.log(this.bar) }, ...
  • 這裡給大家分享我在網上總結出來的一些知識,希望對大家有所幫助 什麼是跨域? 跨域不是問題,是一種安全機制。瀏覽器有一種策略名為同源策略,同源策略規定了部分請求不能被瀏覽器所接受。 值得一提的是:同源策略導致的跨域是瀏覽器單方面拒絕響應數據,伺服器端是處理完畢並做出了響應的。 什麼是同源策略 一個ur ...
  • 1.CSS、SCSS、Sass CSS是開發人員熟知的一種用於頁面樣式開發的語言,可以通過內容的分離控制減少代碼的重覆性,降低代碼的複雜程度。 Sass與 SCSS 都是 CSS 預處理器,可包含在基於 CSS 的 UI(用戶界面)或前端框架中以簡化開發。Sass 與 SCSS 框架在高級別的 CS ...
  • 通常,不同的公司里有著不同的編碼規範,主要是從代碼得準確性、穩定性、可讀性等地方著手制定,以提高團隊成員之間的協作效率,這裡主要是列出一些常見的編碼規範。 ...
  • 隨著移動互聯網發展,手機端購物已成為人們生活的常態。人們在搜索商品時採用的手段也越來越豐富,當前的主要搜索方式是文本搜索與拍照搜索。 ...
  • 1 簡介 之前在文章《dapr入門與本地托管模式嘗試》中介紹了dapr和本地托管,本文我們來介紹如果在代碼中使用dapr的服務調用功能,並把它整合到Spring Boot中。 Dapr服務調用的邏輯如下: 本次實驗會創建兩個服務: pkslow-data,提供數據服務,用於返回數據; pkslow- ...
一周排行
    -Advertisement-
    Play Games
  • 前言 在我們開發過程中基本上不可或缺的用到一些敏感機密數據,比如SQL伺服器的連接串或者是OAuth2的Secret等,這些敏感數據在代碼中是不太安全的,我們不應該在源代碼中存儲密碼和其他的敏感數據,一種推薦的方式是通過Asp.Net Core的機密管理器。 機密管理器 在 ASP.NET Core ...
  • 新改進提供的Taurus Rpc 功能,可以簡化微服務間的調用,同時可以不用再手動輸出模塊名稱,或調用路徑,包括負載均衡,這一切,由框架實現並提供了。新的Taurus Rpc 功能,將使得服務間的調用,更加輕鬆、簡約、高效。 ...
  • 順序棧的介面程式 目錄順序棧的介面程式頭文件創建順序棧入棧出棧利用棧將10進位轉16進位數驗證 頭文件 #include <stdio.h> #include <stdbool.h> #include <stdlib.h> 創建順序棧 // 指的是順序棧中的元素的數據類型,用戶可以根據需要進行修改 ...
  • 前言 整理這個官方翻譯的系列,原因是網上大部分的 tomcat 版本比較舊,此版本為 v11 最新的版本。 開源項目 從零手寫實現 tomcat minicat 別稱【嗅虎】心有猛虎,輕嗅薔薇。 系列文章 web server apache tomcat11-01-官方文檔入門介紹 web serv ...
  • C總結與剖析:關鍵字篇 -- <<C語言深度解剖>> 目錄C總結與剖析:關鍵字篇 -- <<C語言深度解剖>>程式的本質:二進位文件變數1.變數:記憶體上的某個位置開闢的空間2.變數的初始化3.為什麼要有變數4.局部變數與全局變數5.變數的大小由類型決定6.任何一個變數,記憶體賦值都是從低地址開始往高地 ...
  • 如果讓你來做一個有狀態流式應用的故障恢復,你會如何來做呢? 單機和多機會遇到什麼不同的問題? Flink Checkpoint 是做什麼用的?原理是什麼? ...
  • C++ 多級繼承 多級繼承是一種面向對象編程(OOP)特性,允許一個類從多個基類繼承屬性和方法。它使代碼更易於組織和維護,並促進代碼重用。 多級繼承的語法 在 C++ 中,使用 : 符號來指定繼承關係。多級繼承的語法如下: class DerivedClass : public BaseClass1 ...
  • 前言 什麼是SpringCloud? Spring Cloud 是一系列框架的有序集合,它利用 Spring Boot 的開發便利性簡化了分散式系統的開發,比如服務註冊、服務發現、網關、路由、鏈路追蹤等。Spring Cloud 並不是重覆造輪子,而是將市面上開發得比較好的模塊集成進去,進行封裝,從 ...
  • class_template 類模板和函數模板的定義和使用類似,我們已經進行了介紹。有時,有兩個或多個類,其功能是相同的,僅僅是數據類型不同。類模板用於實現類所需數據的類型參數化 template<class NameType, class AgeType> class Person { publi ...
  • 目錄system v IPC簡介共用記憶體需要用到的函數介面shmget函數--獲取對象IDshmat函數--獲得映射空間shmctl函數--釋放資源共用記憶體實現思路註意 system v IPC簡介 消息隊列、共用記憶體和信號量統稱為system v IPC(進程間通信機制),V是羅馬數字5,是UNI ...