完美的【去重留一】SQL

DELETE consum_record
FROM
 consum_record, 
 (
  SELECT
   min(id) id,
   user_id,
   monetary,
   consume_time
  FROM
   consum_record
  GROUP BY
   user_id,
   monetary,
   consume_time
  HAVING
   count(*) > 1
 ) t2
WHERE
 consum_record.user_id = t2.user_id 
 and consum_record.monetary = t2.monetary
 and consum_record.consume_time = t2.consume_time
AND consum_record.id > t2.id;

上面這條sql語句，仔細看一下，揣摩出思路也不難，大概也分為3步來理解：

(SELECT min(id) id, user_id, monetary, consume_time FROM consum_record GROUP BY user_id, monetary, consume_time HAVING count(*) > 1 ) t2 查詢出重覆記錄形成一個集合（臨時表t2），集合里是每種重覆記錄的最小ID

consum_record.user_id = t2.user_id and consum_record.monetary = t2.monetary and consum_record.consume_time = t2.consume_time 關聯 判斷重覆基準的欄位

根據條件，刪除原表中id大於t2中id的記錄