FastJson轉Java對像欄位不區分大小寫

昨天遇到參數key大小寫不一致導致校驗簽名失敗的問題，查了很長時間才找到原因。看了一下FastJson源碼，發現JSON.toObject中轉換成對象的時候會忽略大小寫。

所以，當使用了JSON.toObject將json轉成Java對象後，再用JSON.toObject轉成json，key值就變了。

寫個方法驗證一下：

public class Person {
	private String nickName;

	public String getNickName() {
		return nickName;
	}

	public void setNickName(String nickName) {
		this.nickName = nickName;
	}
	
}

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;

public class JsonToObject {

	public static void main(String[] args) {
		JSONObject json1 = new JSONObject();
		json1.put("nickName", "shawn1");
		System.out.println(json1);
		Person p1 = json1.toJavaObject(Person.class);
		System.out.println(p1.getNickName());
		JSONObject json11 = (JSONObject)JSON.toJSON(p1);
		System.out.println(json11);
		System.out.println("--------------------");
		
		JSONObject json2 = new JSONObject();
		json2.put("nickname", "shawn2");
		System.out.println(json2);
		json2.toJavaObject(Person.class);
		Person p2 = json2.toJavaObject(Person.class);
		System.out.println(p2.getNickName());
		JSONObject json22 = (JSONObject)JSON.toJSON(p2);
		System.out.println(json22);
		System.out.println("--------------------");
		
		JSONObject json3 = new JSONObject();
		json3.put("nIcknAme", "shawn3");
		System.out.println(json3);
		json3.toJavaObject(Person.class);
		Person p3 = json3.toJavaObject(Person.class);
		System.out.println(p3.getNickName());
		JSONObject json33 = (JSONObject)JSON.toJSON(p3);
		System.out.println(json33);
		System.out.println("--------------------");
	}	

}

輸出：

{"nickName":"shawn1"}
shawn1
{"nickName":"shawn1"}
--------------------
{"nickname":"shawn2"}
shawn2
{"nickName":"shawn2"}
--------------------
{"nIcknAme":"shawn3"}
shawn3
{"nickName":"shawn3"}
--------------------

JSON.toObject中轉換成對象的時候忽略了大小寫，可以增強健壯性，但Java類是區分大小寫的，如果有兩個僅僅帶小寫不同的屬性，可能就出問題了。

給Person增加一個屬性再試一下：

public class Person {
	private String nickName;

	public String getNickName() {
		return nickName;
	}

	public void setNickName(String nickName) {
		this.nickName = nickName;
	}
	
	private String nickname;

	public String getNickname() {
		return nickname;
	}

	public void setNickname(String nickname) {
		this.nickname = nickname;
	}
	
}

import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;

public class JsonToObject {

	public static void main(String[] args) {
		JSONObject json1 = new JSONObject();
		json1.put("nickName", "shawn1");
		System.out.println(json1);
		Person p1 = json1.toJavaObject(Person.class);
		System.out.println("nickName:"+p1.getNickName()+"\t nickname:"+p1.getNickname());
		JSONObject json11 = (JSONObject)JSON.toJSON(p1);
		System.out.println(json11);
		System.out.println("--------------------");
		
		JSONObject json2 = new JSONObject();
		json2.put("nickname", "shawn2");
		System.out.println(json2);
		json2.toJavaObject(Person.class);
		Person p2 = json2.toJavaObject(Person.class);
		System.out.println("nickName:"+p2.getNickName()+"\t nickname:"+p2.getNickname());
		JSONObject json22 = (JSONObject)JSON.toJSON(p2);
		System.out.println(json22);
		System.out.println("--------------------");
		
		JSONObject json3 = new JSONObject();
		json3.put("nIcknAme", "shawn3");
		System.out.println(json3);
		json3.toJavaObject(Person.class);
		Person p3 = json3.toJavaObject(Person.class);
		System.out.println("nickName:"+p3.getNickName()+"\t nickname:"+p3.getNickname());
		JSONObject json33 = (JSONObject)JSON.toJSON(p3);
		System.out.println(json33);
		System.out.println("--------------------");
	}	

}

輸出：

{"nickName":"shawn1"}
nickName:shawn1	 nickname:null
{"nickName":"shawn1"}
--------------------
{"nickname":"shawn2"}
nickName:null	 nickname:shawn2
{"nickname":"shawn2"}
--------------------
{"nIcknAme":"shawn3"}
nickName:null	 nickname:shawn3
{"nickname":"shawn3"}
--------------------

這個結果符合你的預期嗎？

所以，用JSON.toObject的時候還是得慎重。

以上。

https://wangxuan.me/tech/2023/06/02/FastJson-convert-json-to-Java-Object-field-ignore-case.html